7*7 + 11 = 60 cows. Cows to each pillar are 7,7,7,7,7,7,7, & 11 tied common to pole/ pillar 8& 9. Sanjay C. By tying one cow to 2 pillars, the number of ties can be changed to the next odd number 61.
How can 50 cows be tied on 9 pillars with an odd number on each pillar?
Answer
- 7 cows on 4 pillars = 28.
- 3 cows on 3 pillars = 9.
- 9 cows on 1 pillar. =
- 4 cows on 1 pillar = 4. = 28+9+9+4 = 50. acobdarfq and 59 more users found this answer helpful. Thanks 39. 3.4. (20 votes)
How can 100 cows be tied on 11 pillars with an odd number on each pillar?
U can tie 99 cows in 9 pillars …. like 11 cows per pillar…. and then one cow will be remaining so that the number of cows per pillar will not be odd fully. It means we have 5+4=9 pillor and 60+40=100 cows.
How can you add 9 odd numbers to get 50?
FACT:Sum of odd number of odd integers is always odd. So, there can be no way by which the sum of 9 odd numbers is 50.
How do you tie 90% camels in 9 pillars?
Very Simple ! Tie any one ( odd number ) of 90 to any one of nine & then tie all the remaining 89 ( again odd number ) to every pillar of remaining 8 pillars.
How can 50 eggs fill in 9 boxes with only an odd number?
Just divide 50 cows in 9 groups, you have 50/9=5.5555555555……. (do not round up). So you essentially have an “odd” number (in fact, lots of them) at each digit, on each pillar.
How can 42 cows be tied on 7 pillars with an odd number on each?
This is impossible because the sum of 7 odd numbers is bound to be another odd number, but 42 is even not odd. Tie 3 cows to pillar #1, 3 cows to pillar #2, 7 cows to pillar #3 and 7 cows to pillar #4. Now every pillar that has cows has an odd number.
What 3 odd numbers add up to 50?
3 odd numbers will always equal an odd number, and 50 is an even number. Therefore, 3 odd numbers cannot add up to 50.
